(2n^2-5n)/n+9=2n^2

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Solution for (2n^2-5n)/n+9=2n^2 equation: 



(2n^2-5n)/n+9=2n^2

We move all terms to the left:

(2n^2-5n)/n+9-(2n^2)=0



Domain of the equation: n!=0

n∈R



determiningTheFunctionDomain
-2n^2+(2n^2-5n)/n+9=0

We multiply all the terms by the denominator


-2n^2*n+(2n^2-5n)+9*n=0

We add all the numbers together, and all the variables

-2n^2*n+9n+(2n^2-5n)=0

Wy multiply elements

-2n^3+9n+(2n^2-5n)=0

We get rid of parentheses

-2n^3+2n^2+9n-5n=0

We do not support enpression: n^3

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